The value of sum
Consider the sequence of expressions
(define sum 0)
(define (accum x)
(set! sum (+ x sum))
sum)
(define seq (stream-map accum (stream-enumerate-interval 1 20)))
(define y (stream-filter even? seq))
(define z (stream-filter (lambda (x) (= (remainder x 5) 0))
seq))
(stream-ref y 7)
(display-stream z)
What is the value of sum after each of the above expressions is evaluated? What is the printed response to evaluating the stream-ref and display-stream expressions? Would these responses differ if we had implemented (delay <exp>) simply as (lambda () <exp>) without using the optimization provided by memo-proc ? Explain.
This is a great example of pointless academic exercise. How would it make anyone a better programmer??