Show that it is impossible to write a procedure halts?
Given a one-argument procedure p and an object a , p is said to ''halt'' on a if evaluating the expression (p a) returns a value (as opposed to terminating with an error message or running forever). Show that it is impossible to write a procedure halts? that correctly determines whether p halts on a for any procedure p and object a . Use the following reasoning: If you had such a procedure halts? , you could implement the following program:
(define (run-forever) (run-forever))
(define (try p)
(if (halts? p p)
(run-forever)
'halted))
Now consider evaluating the expression (try try) and show that any possible outcome (either halting or running forever) violates the intended behavior of halts? .