Differentiation of arbitrary numbers of terms
Extend the differentiation program to handle sums and products of arbitrary numbers of (two or more) terms. Then the last example above could be expressed as
(deriv '(* x y (+ x 3)) 'x)
Try to do this by changing only the representation for sums and products, without changing the
deriv
procedure at all. For example, the
addend
of a sum would be the first term, and the
augend
would be the sum of the rest of the terms.