Код Ревью
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#| BEGIN (Write your solution here) |#
(define (element-of-set? x set)
(cond ((null? set) #f)
((equal? x (car set)) #t)
(else (element-of-set? x (cdr set)))))
(define (adjoin-set x set)
(cons x set)
)
(define (intersection-set set1 set2)
(cond ((or (null? set1) (null? set2)) '())
((element-of-set? (car set1) set2)
(cons (car set1) (intersection-set (cdr set1) set2)))
(else (intersection-set (cdr set1) set2))))
(define (union-set set1 set2)
(if (null? set2) set1
(union-set (adjoin-set (car set2) set1) (cdr set2))
)
)
#| END |#